Question

Rate for Run2 :0.848x10^-6
[S2O8^2-] = 0.0235
0.0235/0.0117 = 2.01-----------------(1)

Rate for Run 3:0.398x10^-6
[S2O8^2-] = 0.0117
0.848x10^-6/0.398x10^-6 = 2.13----(2)
Run 5 & 6 =2.01--------------------------- (3)
=1.92--------------------------- (4)
So ,the rates of changesequal to 2 right?
Thus, m (we use as y) willbe 1.

b) determine the order of reaction with respect to I⁻.

Show at least two detailed mathematical calculations

using the data as you did the previous question.

For this question.. If I use Run 4and7 , [I⁻] values are 0.0157 and0.00785

0.0157/0.00785=2 But, the rate is 0.205x10^-6 and 0.210x10^-6which is =1

Then what is n( we useas x) value???? 2????

And What is averageorder with respect to [I⁻]?