1. Calculate the standard entropy change for the reaction:
2NO2(g)+ H2O(g) --> HNO2(g) +HNO3(g)
Use thefollowing data: S°(NO2(g)) = 240.0 J mol-1K-1;S°(H2O(g)) = 118.7 J mol-1K-1; S°(HNO2(g)) =59.59 J mol-1K-1; S°(HNO3(g)) = 266.2 Jmol-1K-1.
A. -272.9 J/K
B. 272.9 J/K
C. 32.9 J/K
D. -32.9 J/K
E. 136.5 J/K
2. Calculate the standard free energy change, and determine whether ornot the following reaction is spontaneous under standardconditions:
H2O2(l)--> H2O(l) + ½O2(g)
Use thefollowing values for ÎGf°: H2O2(l)= -120.4 kJ/mol; H2O(l) = -237.2 kJ/mol.
A. -457.6 kJ; spontaneous
B. 475.6 kJ; not spontaneous
C. -116.8 kJ; spontaneous
D. 116.8 kJ; not spontaneous
E. -287.2 kJ; spontaneous
3. Youhave probably heard the two sayings, "Nothing lasts forever" and"Diamonds are forever". They can't both be right, which one iscorrect?! Calculate the standard free energychange at 298K for the conversion of diamonds to graphite anddetermine whether or not the reaction is spontaneous under standardconditions:
C(diamond)--> C(graphite);
ÎHf°(diamond)= 1.895 kJ/mol; S°(diamond) = 2.337 J mol- 1K-1; S°(graphite) =5.740 J mol-1K-1.
A. 2.19 kJ; not spontaneous
B. -1.90 kJ; spontaneous
C. -2.90 kJ; spontaneous
D. 1.90 kJ; not spontaneous
E. 4.04 kJ; not spontaneous
PLEASE SHOWHOW YOU GET THE ANSWER---THANKS!
1. Calculate the standard entropy change for the reaction:
2NO2(g)+ H2O(g) --> HNO2(g) +HNO3(g)
Use thefollowing data: S°(NO2(g)) = 240.0 J mol-1K-1;S°(H2O(g)) = 118.7 J mol-1K-1; S°(HNO2(g)) =59.59 J mol-1K-1; S°(HNO3(g)) = 266.2 Jmol-1K-1.
A. -272.9 J/K
B. 272.9 J/K
C. 32.9 J/K
D. -32.9 J/K
E. 136.5 J/K
2. Calculate the standard free energy change, and determine whether ornot the following reaction is spontaneous under standardconditions:
H2O2(l)--> H2O(l) + ½O2(g)
Use thefollowing values for ÎGf°: H2O2(l)= -120.4 kJ/mol; H2O(l) = -237.2 kJ/mol.
A. -457.6 kJ; spontaneous
B. 475.6 kJ; not spontaneous
C. -116.8 kJ; spontaneous
D. 116.8 kJ; not spontaneous
E. -287.2 kJ; spontaneous
3. Youhave probably heard the two sayings, "Nothing lasts forever" and"Diamonds are forever". They can't both be right, which one iscorrect?! Calculate the standard free energychange at 298K for the conversion of diamonds to graphite anddetermine whether or not the reaction is spontaneous under standardconditions:
C(diamond)--> C(graphite);
ÎHf°(diamond)= 1.895 kJ/mol; S°(diamond) = 2.337 J mol- 1K-1; S°(graphite) =5.740 J mol-1K-1.
A. 2.19 kJ; not spontaneous
B. -1.90 kJ; spontaneous
C. -2.90 kJ; spontaneous
D. 1.90 kJ; not spontaneous
E. 4.04 kJ; not spontaneous
PLEASE SHOWHOW YOU GET THE ANSWER---THANKS!