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6 Nov 2019
A gas of unknown molar mass was allowed to effuse through a smallopening under constant pressure conditions. It required 184 s for1.00 L of this gas to effuse. Under identical experimentalconditions it required 506 s for 1.00 L of chlorotrifluoromethane(CClF3) gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter thetime required for effusion; that is, rate and time are inverselyproportional.)
Options:
a) The molar mass is 287.3 g/mol.
b) The molar mass is 790.0 g/mol.
c) The molar mass is 63.0 g/mol.
d) The molar mass is 173.2 g/mol.
e) The molar mass is 13.8 g/mol.
A gas of unknown molar mass was allowed to effuse through a smallopening under constant pressure conditions. It required 184 s for1.00 L of this gas to effuse. Under identical experimentalconditions it required 506 s for 1.00 L of chlorotrifluoromethane(CClF3) gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter thetime required for effusion; that is, rate and time are inverselyproportional.)
Options:
a) The molar mass is 287.3 g/mol.
b) The molar mass is 790.0 g/mol.
c) The molar mass is 63.0 g/mol.
d) The molar mass is 173.2 g/mol.
e) The molar mass is 13.8 g/mol.
Options:
a) The molar mass is 287.3 g/mol.
b) The molar mass is 790.0 g/mol.
c) The molar mass is 63.0 g/mol.
d) The molar mass is 173.2 g/mol.
e) The molar mass is 13.8 g/mol.
Collen VonLv2
6 Nov 2019