Extensive and Intensive Properties and Graphing. Seg2: Data Analysis A student's data for the silver and gold-colored cylinders has been provided on Tables 1 and 2 below. : Cold-Colored Cylinder Data xtensive and Intensive Properties and Graphing. nd Intensive Properties and Graphing. Seg3: Calculations with D, m, and V A student's data for the silver and gold-colored cylinders has been provided in Tables 1 and 2 below Using the equation D = m/V, calculate the mass of a sample of gold-colored metal that would correspond to a volume of 125 cm3 Provide your answer in the correct units and number of significant figures. Using the equation D = m/V, calculate the volume of a sample of the ilver-colored meta that corresponds to 2.25 kg (1000 g = 1 kg)Provide your answer in the correct units and number of significant figures. You may need to use the graph you made from these data tables to answer the questions in this section.
Show transcribed image textExtensive and Intensive Properties and Graphing. Seg2: Data Analysis A student's data for the silver and gold-colored cylinders has been provided on Tables 1 and 2 below. : Cold-Colored Cylinder Data xtensive and Intensive Properties and Graphing. nd Intensive Properties and Graphing. Seg3: Calculations with D, m, and V A student's data for the silver and gold-colored cylinders has been provided in Tables 1 and 2 below Using the equation D = m/V, calculate the mass of a sample of gold-colored metal that would correspond to a volume of 125 cm3 Provide your answer in the correct units and number of significant figures. Using the equation D = m/V, calculate the volume of a sample of the ilver-colored meta that corresponds to 2.25 kg (1000 g = 1 kg)Provide your answer in the correct units and number of significant figures. You may need to use the graph you made from these data tables to answer the questions in this section.
Chemists often use molarity M, in moles/liter, to measure the concentration of solutions. Molarity is a common unit of concentration because the volume of a liquid is very easy to measure. However, the drawback of using molarity is that volume is a temperature-dependent quantity. As temperature changes, density changes, which affects volume. Volume markings for most laboratory glassware are calibrated for room temperature, about 20âC.
Fortunately, there are several other ways of expressing concentration that do not involve volume and are therefore temperature independent.
A 2.350Ã10â2M solution of NaCl in water is at 20.0âC. The sample was created by dissolving a sample of NaCl in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 999.4 mL . The density of water at 20.0âC is 0.9982 g/mL.
Part A
Calculate the molality of the salt solution.
Express your answer to four significant figures and include the appropriate units.
mNaCl =
.0235m
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Your answer has units of mol/L of water. You need to convert the volume of water to kilograms using the density provided.
Part B
Calculate the mole fraction of salt in this solution.
Express the mole fraction to four significant figures.
ÏNaCl =
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Part C
Calculate the concentration of the salt solution in percent by mass.
Express your answer to four significant figures and include the appropriate units.
percent by mass NaCl =
%
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Part D
Calculate the concentration of the salt solution in parts per million.
Express your answer as an integer to four significant figures and include the appropriate units.