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The combustion of octane, C8H18, proceeds according to the reaction 2 C8H18(l) + 25 O2(g) --> 16 CO2(g) + 18 H2O(l) If 474 mol of octane combusts, what volume of carbon dioxide is produced at 19.0*C and 0.995 atm?
The combustion of octane, C8H18, proceeds according to the reaction 2 C8H18(l) + 25 O2(g) --> 16 CO2(g) + 18 H2O(l) If 474 mol of octane combusts, what volume of carbon dioxide is produced at 19.0*C and 0.995 atm?
Jarrod RobelLv2
19 Jan 2019
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