🏷️ LIMITED TIME OFFER: GET 20% OFF GRADE+ YEARLY SUBSCRIPTION →
Log in
Chemistry
4
answers
0
watching
2,659
views

What is the chemical formula of a diamond?

Watch
4
answers
0
watching
2,659
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share
Already have an account? Log in
Share
Already have an account? Log in
Share
Verified Answer
Nelly Stracke
Nelly StrackeLv2
15 May 2019
Already have an account? Log in
Joey Tang
Joey Tang
Bachelor’s Degree in Chemistry from McMaster University
27 May 2020

Answer verification

This is a step by step verification of the answer by our certified expert.
Subscribe to our livestream channel for more helpful videos.
Subscribe
Share
discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Basic Chemistry
5 Edition,
Timberlake
ISBN: 9780134138046
Principles of Chemistry Molecular Approach
4th Edition,
Tro
ISBN: 9780134112831
Principles of Chemistry Molecular Approach
3rd Edition, 2014
Tro
ISBN: 9780321971944
Chemistry: Structure and Properties
2nd Edition,
Tro
ISBN: 9780134293936
Chemistry: A Molecular Approach
3rd Edition,
Tro
ISBN: 9780321809247
Chemistry: A Molecular Approach
5th Edition,
Tro
ISBN: 9780134874371
Principles of Chemistry: A Molecular Approach
4th Edition,
Tro
ISBN: 9780134895741
Chemistry: The Central Science
14th Edition, 2017
Brown
ISBN: 9780134414232

Related questions

What is the chemical formula of a diamond?

What is the chemical formula for diamond? 

11. Given data: Molar enthalpy of diamond: h298K(diamond) = 1900 J/mol Molar entropy of graphite and diamond: s298(graphite) = 5.6 J/(Kmol), s298K(diamond) = 2.4 J/(Kmol), Molar volume of graphite and diamond: v298,1atm (graphite) = 6.0 cm3/mol, v298,1atm (diamond) = 3.4 cm3/mol Molar constant pressure heat capacity of graphite and diamond: cp(graphite) = 8.5 J/(Kmol), cp(diamond) = 6.0 J/(Kmol) Isothermal compressibility of graphite and diamond:  (graphite) =3x10-6/atm,ï€ ï¢ (diamond) = 2x10- 7/atm Constant pressure thermal expansion coefficient of graphite and diamond: (graphite) = 3x10- 5/K,  (diamond) = 10-5/K

Calculate: The difference in the chemical potential between diamond and graphite as a function of temperature at 1atm and plot it (assuming constant cp)

Weekly leaderboard

Home
Homework Help 3,900,000
Chemistry 830,000
Start filling in the gaps now
Log in