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10 Nov 2019
Please answer and explain! Thank you! The reaction 2NO_2 rightarrow 2NO + O_2 obeys the rate law: Delta [O_2]/Delta t = (1.40 times 10^-2 sec)[NO_2]^2 at 500 K. If the initial concentration of NO_2 is 1.00 M, how, long will it take for the [NO_2] to decrease to 35 8% of its initial value?
Please answer and explain! Thank you!
The reaction 2NO_2 rightarrow 2NO + O_2 obeys the rate law: Delta [O_2]/Delta t = (1.40 times 10^-2 sec)[NO_2]^2 at 500 K. If the initial concentration of NO_2 is 1.00 M, how, long will it take for the [NO_2] to decrease to 35 8% of its initial value?
Jarrod RobelLv2
12 Jul 2019