Question

1.Given the chemical reaction: 3 C_(graphite) + 4 H₂(g) --> C₃H₈(g)

Calculate the ∆Hrxn using Hess's Law and the following information:

C₃H₈(g) + 5 O₂(g) --> 3 CO₂(g) + 4 H₂O(l) ∆H = -2220 kJ/mol

C_(graphite) + O₂(g) --> CO₂(g) ∆H = -393.5 kJ/mol

H₂(g) + 1/2 O₂(g) --> H₂O(l) ∆H = -285.8 kJ/mol

2.Given the chemical reaction: C₃H₈(g) + 5 O₂(g) --> 3 CO₂(g) + 4 H₂O(l); ∆H = -2220 kJ/mol, calculate the heat given off when 0.48 g of C₃H₈ reacts with oxygen according to the reaction.

3.Given the chemical reaction: C₃H₈(g) + 5 O₂(g) --> 3 CO₂(g) + 4 H₂O(l); ∆H = -2220 kJ/mol, calculate the change in temperature of 150 g of water in a calorimeter when 0.48 g of C₃H₈ reacts with oxygen.