4of6 Calculating equilibrium concentrations when the net reaction proceeds forward Consider mixture B, which will cause the net reaction to proceed forward. net â Concentration (M) initial change: equilibrium [X] 0.100 +2 0.100 +r [XY] 0.500 0.100 0.500 a 0.100+a The change in concentration, z, is negative for the reactants because they are consumed and positive for the products because they are produced. â¼ Part B Based on a Ke value of 0.230 and the given data table, what are the equilibriunm concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. View Available Hint(s) Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C, which will cause the net reaction to proceed in reverse â net Concentration (M) initial change equilibrium: 0.200 0.300 0.300 0.200+x 0.300 -az 0.300 r The change in concentration, z, is positive for the reactants because they are produced and negative for the products because they are consumed. â¼ Part C Based on a Kc value of 0.230 and the data table given, what are the equilibriunm concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. View Available Hint(s)