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1.) Assume that each drop of Pb(NO3)2 contains 1.7 mg of Pb(NO3)2 and that each drop of KI contains 0.83 mg of KI. Given this information, determine the limiting reagent and calculate the theoretical yield for each reaction Tube 1-5 listed in the table below.
Table 1.1
Drops of water Drops of Pb(NO3)2 Drops of KI Lead:Iodine Ration Tube 1 32 12 4 3:1 Tube 2 30 12 6 2:1 Tube 3 24 12 12 1:1 Tube 4 12 12 24 1:2 Tube 5 0 12 36 1:3
1.) Assume that each drop of Pb(NO3)2 contains 1.7 mg of Pb(NO3)2 and that each drop of KI contains 0.83 mg of KI. Given this information, determine the limiting reagent and calculate the theoretical yield for each reaction Tube 1-5 listed in the table below.
Table 1.1
Drops of water | Drops of Pb(NO3)2 | Drops of KI | Lead:Iodine Ration | ||
Tube 1 | 32 | 12 | 4 | 3:1 | |
Tube 2 | 30 | 12 | 6 | 2:1 | |
Tube 3 | 24 | 12 | 12 | 1:1 | |
Tube 4 | 12 | 12 | 24 | 1:2 | |
Tube 5 | 0 | 12 | 36 | 1:3 |
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Keith LeannonLv2
15 Sep 2019
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