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11 Nov 2019

Electron radii problem. I thought that P(-3) would have the smallest radius because it is the same as MG, but the answer key says CA 2+ is the smallest. Can anyone explain this? thanks.

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Trinidad Tremblay
Trinidad TremblayLv2
10 Oct 2019

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Related questions

Explain clearly, all of the number

Ionic Radii

The size of ions as measured by ionic radii varies in a systematic manner. The size of the ion can be explained in part by effective nuclear charge, Zeff, which is the net nuclear charge felt by an electron. The effective nuclear charge takes into account the actual nuclear charge and the shielding of this charge by inner electrons. When an atom loses electrons, the resulting cation is smaller both because the remaining electrons experience a larger Zeff and because these electrons are usually in orbitals closer to the nucleus than the electrons that were lost. The more electrons that are lost, the smaller the ion becomes.

Similarly, when an atom gains electrons, the resulting anion is larger owing to both increased electron-electron repulsions and a reduction in Zeff. The more electrons that are gained, the larger the ion becomes.

Part A

Rank the following ions in order of decreasing radius: O2−,S2−,Se2−,Te2−, and Po2−. Use the periodic table as necessary.

Rank from largest to smallest radius. To rank items as equivalent, overlap them.

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Part B

Rank the following items in order of decreasing radius: Na, Na+, and Na−.

Rank from largest to smallest radius. To rank items as equivalent, overlap them.

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Part C

The following ions contain the same number of electrons. Rank them in order of decreasing ionic radii.

Rank from largest to smallest radius. To rank items as equivalent, overlap them.

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