kJ/mo D-glucose + ATPâ D-glucose-6-phosphate + ADP Î Go' =-16.7 D-glucose-6-phosphate â D-fructose-6-phosphate D-fructose-6-diphosphate + ATP â D fructose-1,6-diphosphate + ADP Î G"--14.2 D-fructose-1,6-diphosphate â glyceraldehyde-3-phosphate + dihydroxyacetone phosphate dihydroxyacetone phosphate â glyceraldehyde-3-phosphate glyceraldehyde-3-phosphate + phosphate + NAD+ â 1,3-diphosphoglycerate + NADH + H+ 1,3-diphosphoglycerate + ADPâ 3-phosphoglycerate + ATP 3-phosphoglycerate â 2-phosphoglycerate , Î Go= + 6.3 Î Go:-18.8 Î Go'= +4.6 Î Go, = +1.7 Î Go:-31.4 Î Go, =-25.1 Î Go, =-19.8 Î Go' =-23.7 2-phosphoglycerate â 2-phosphoenolpyruvate + H2O 2-phosphoenolpyruvate + ADP â pyruvate + ATP pyruvate + NADH + H+ â lactate + NAD+ pyruvate â acetaldehyde+ CO2 acetaldehyde + NADH + H+ â ethanol + NAD+ 14. Above are the ÎGo, values for the reactions of glycolysis. Some of these reactions are positive. How can these reactions occur within a cell even though they have a positive ÎGo? what are the ways that a cell can drive a reaction with a positive ÎGor ?