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12 Nov 2019
The equilibrium constant for the reaction below is 5.88 X 10 -3 at room temperature. Suppose 15.6 g of N2O4 is placed in a 5.0 L flask at room temperature. What will the [NO2] be at equilibrium?
N2O4(g) â2NO2(g)
The equilibrium constant for the reaction below is 5.88 X 10 -3 at room temperature. Suppose 15.6 g of N2O4 is placed in a 5.0 L flask at room temperature. What will the [NO2] be at equilibrium?
N2O4(g) â2NO2(g)
Bunny GreenfelderLv2
11 Jan 2019