1
answer
0
watching
674
views

Solid ammonium carbonate, NH4CO2NH2, decomposes at 25 C to ammoniaand carbon dioxide. NH4CO2NH2(s)<--->2NH3(g)+CO2(g) Theequilibrium constant for the decomposition at 25 C is 2.3x10^-4. At25 C, 7.50 g of NH4CO2NH2 is sealed in a 10.0-L flask and allowedto decompose. a. What is the total pressure in the flask whenequilibrium is established? b. What percentage of NH4CO2NH2decomposed? c. Can you state from the data calculated that thedecomposition took place slowly?

For unlimited access to Homework Help, a Homework+ subscription is required.

Irving Heathcote
Irving HeathcoteLv2
28 Sep 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Start filling in the gaps now
Log in