In the benzene molecule, carbon atoms form a ring with alternating single and double bonds in between each of them. Each carbon atom forms one ? bond with one carbon atom and one ? and one ? bond with another. The ? bonding electrons are delocalized over the entire molecule. Thus, benzene is a resonance hybrid of two equivalent structures, and the single and double bonds oscillate from one position to the other.Calculate the bond order for one carbon-carbon bond in the benzene molecule, taking ?
and?bonding into consideration.Express your answer numerically.
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In the benzene molecule, carbon atoms form a ring with alternating single and double bonds in between each of them. Each carbon atom forms one sigma bond with one carbon atom and one sigma and one pi bond with another. The pi bonding electrons are delocalized over the entire molecule. Thus, benzene is a resonance hybrid of two equivalent structures, and the single and double bonds oscillate from one position to the other. Calculate the bond order for one carbon-carbon bond in the benzene molecule, taking sigma and pi bonding into consideration. Express your answer numerically.
