Hello, I was hoping someone could just double check my work forthese questions. I'm not asking anyone to actually answer themindividually, just to briefly skim over and see if I'm on the righttrack. The questions seemd pretty straight forward so I'm a bitnervous that I may have done something wrong.
a. FCC - Face Centered Cubic if there are no Cl atoms. 8 Corneratoms, 6 face atoms.
b. Indices: (010) and (1/2,1,1)
c. a = 2*Radius of Cl + 2*Radius of Na = 5.6 Angstrom
d. This structure contains 4 Na atoms and 4 Cl atoms (basicallyjust adding up all the corner atoms, edge atoms, center atoms,etc). Therefore the fraction is 4 * Volume of Na + 4 * Volume of Cl/ a^3. Where the Volume of Na = 4/3 * pi * R(Na)^3
Volume of Cl = 4/3 * pi * R(Cl)^3
Total Volume = a^3
e. (100) plane contains 2 Na and 2 Cl. Therefore the fraction is2 * Area of Na + 2 * Area of Cl / a^2; Where area of Na =pi*R(Na)^2
Area of Cl = pi*R(Cl)^2
Total area = a^2
(110) plane contains 2 Na and 2 Cl. Therefore the same as theabove question except the total area is sqrt(2)*a^2.
That's it, took maybe 5 minutes to do the assignments. That'swhy I'm a bit worried. Again, I'm not asking someone to solve allthe problems, just to look and see if my approaches are correct.Thanks.
