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The following reaction is a single-step, bimolecular reaction: CH3Br+NaOH--->CH3OH+NaBr. When the concentrations of CH3Br and NaOH are both 0.170 M, the rate of the reaction is 0.0090 M/s. (a) What is the rate of the reaction if the concentration of CH3Br is doubled? (b) What is the rate of the reaction if the concentration of NaOH is halved? (c) What is the rate of the reaction if the concentrations of CH3Br and NaOH are both increased by a factor of five?

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Beverley Smith
Beverley SmithLv2
28 Sep 2019
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Joey Tang
Joey Tang
Bachelor’s Degree in Chemistry from McMaster University
16 Apr 2020

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