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15 Nov 2019
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Write the electron configuration for each atom on your own; then complete the sentences to explain the trends in first ionization energy or electron affinity. Match the words in the left column to the appropriate blanks in the sentences on the right Reset Help a single electron The electron affinity of nitrogen is lower (less negative) than that of both carbon and oxygen This trend is best explained by noting that paired electrons have a repulsion than unpaired electrons, and adding an electron to C pair, while adding an electron to N electrostatic a pair of electron:s require electrons to no electrons require electrons to pair. Adding an electron to O greater require electrons to pair; however, since O already has a paired electron, the smaller additional repulsion is than for N does not The first ionization energy of phosphorus is greater than that of sulfur. This trend is best explained by noting that in P atoms each 3p orbital contains in S atoms one 3p orbital contains electrons have a an electron from S requires less energy does , while The value of Z is for P, but paired electrostatic repulsion than unpaired electrons. Therefore, removing
I do rate the answer, please answer it serious
Write the electron configuration for each atom on your own; then complete the sentences to explain the trends in first ionization energy or electron affinity. Match the words in the left column to the appropriate blanks in the sentences on the right Reset Help a single electron The electron affinity of nitrogen is lower (less negative) than that of both carbon and oxygen This trend is best explained by noting that paired electrons have a repulsion than unpaired electrons, and adding an electron to C pair, while adding an electron to N electrostatic a pair of electron:s require electrons to no electrons require electrons to pair. Adding an electron to O greater require electrons to pair; however, since O already has a paired electron, the smaller additional repulsion is than for N does not The first ionization energy of phosphorus is greater than that of sulfur. This trend is best explained by noting that in P atoms each 3p orbital contains in S atoms one 3p orbital contains electrons have a an electron from S requires less energy does , while The value of Z is for P, but paired electrostatic repulsion than unpaired electrons. Therefore, removing