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Percent recovery of a mixture.

Hi all so I posted earlier about finding the percent composition of a mixture

The mixture is
Benzoic acid 95.61g
Anisole 243.48g
o-toluidine 296.16g
brought to volume with 2L of methylene chloride.,

which someone answered with this.

mass percent composition = mass of the solute /mass of solution*100

mass of methylene= 2L = 2000ml*1.33 = 2660 grams

density of methylene= 1.33 g/ml

mass of solution = 3295.25 grams

Benzoicacid = 95.61/3295.25*100 = 2.90%

Anisole = 243.48/3295.25*100 = 7.39%
o-toluidine = 296.16/3295.25*100 = 8.98%

in my lab we are supposed to calculate the percent composition of the stock above,

From this info i need the theoretical percent recovery of the 10 mL sample we used and the actual percent recovery of the 10 mL sample

here are the values i got for actual, im confused on what I need to do. pls help

Weight of o-toluidine = 2.11 g

Weight of benzoic acid = 0.05 g

Weight of anisole = 0.16 g

Total recovered mass = 2.32 g

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Casey Durgan
Casey DurganLv2
28 Sep 2019

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