Use the following to calculate Delta H degree_lattice of NaCl: Na(s) rightarrow Na(g) Delta H degree = 109 kJ Cl_2(g) rightarrow 2Cl(g) Delta H degree = 243 kJ Na(g) rightarrow Na^+(g) + e^- Delta H degree - 496 kJ Cl(g) + e^- rightarrow Cl^-(g) Delta H degree = -349 kJ Na(s) + 1/2 Cl_2(g) rightarrow NaCl(s) Delta H degree = -411 kJ Compared with the lattice energy of LiF (1050 kJ/mol), is the magnitude of the value for NaCl what you expected? Explain.
