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17 Nov 2019

Using the Henderson-Hasselbach equation calculate the charge on these amino acids the various pH's in the table

Cys

His

Glu

Asp

Tyr

Arg

Lys

1.5

2.5

3.5

4.5

5.5

6.5

7.5

8.5

9.5

10.5

11.5

12.5

Please show the calculation if you can. And this is a biochemistry question

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Irving Heathcote
Irving HeathcoteLv2
1 Oct 2019

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Related questions

Using the Henderson-Hasselbach equation

1. Calculate the charge of glutamic acid and aspartic side chain at pH 2.5 and pH 11.5. (pKa are 4.2 and 3.9 respectively)

2. Calculate the charge of tyrosine and arginie side chain at pH 3.5 and pH 9.5. (pKa10.1 and 12.5 respectively)

PLEASE SHOW THE CALCULATION ON HOW THE CHARGE WAS OBTAINED. THANKS!! This is a biochemistry question

Titration of a Weak Acid: Data Sheet

Unknown acid: C (letter or number on the unknown bottle)

Mass of the Unknown acid: 0.2016g

Concentration of NaOH(aq): 0.10M

Volume NaOH added

pH

0.5

4.26

1.0

4.42

1.5

4.58

2.0

4.71

2.5

4.82

3.0

4.92

3.5

5.02

4.0

5.11

4.5

5.27

5.0

5.41

5.5

5.48

6.0

5.50

6.5

5.59

7.0

5.73

7.5

5.80

8.0

5.93

8.5

6.06

9.0

6.26

10

6.53

10.5

7.06

11

9.65

11.5

10.98

12

11.23

12.5

11.39

13

11.53

13.5

11.51

14

11.58

14.5

11.65

15

11.72

15.5

11.76

16

11.81

16.5

11.84

17

11.87

17.5

11.89

Calculate Ka for your unknown acid. If your unknown is polyprotic, calculate Ka at both the equivalence points.

(Show work)

possible answers:

Potassium hydrogen phthalate (Monoprotic) [C8H5KO4 ] Molar Mass: 204.2212 4.82 pKa= 5.4

Ascorbic acid (Monoprotic) [C6H8O6 ] Molar Mass: 176.1241 pKa= 4.3

Maleic acid (Diprotic) [C4H4O4 ] Molar Mass: 116.0722 pKa 1= 1.83, pKa2= 6.07

Calculate the initial concentration of your acid. Recall that the original volume of the solution was 0.100 L

[Acid]initial =

Using your calculated value of Ka and the initial concentration of the acid, calculate the initial pH of your acid. Set up an ICE table. You may need to use the quadratic formula.

NaOH(aq) + C8H4O4(aq) ---> NaC8H4O4(aq) + H2O(l)

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