i have some chemistry questions which are about Raoult's law
need all correct answers plz
'Solution B' was prepared by mixing 2.41 g of liquid propanone with 3.10 g of liquid butanone at 30°C in a closed container.
The vapour pressure of pure propanone (C3H6O, molar mass = 58.1 g/mol) at 30°C is 285 mm Hg and that of pure butanone (C4H8O, molar mass = 72.1 g/mol) is 121 mm Hg at the same temperature. From this information, and assuming Raoult's Law applies to his mixture, calculate the values below at 30°C.
(a) the mole fraction of propanone in Solution B
Answer:
(b) the mole fraction of butanone in the solution
Answer:
(c) the partial pressure (in mm Hg) of propanone above Solution B.
Answer:
(d) the partial pressure (in mm Hg) of butanone above Solution B.
Answer:
(e) the mole fraction of propanone in the vapour phase.
Answer:
i have some chemistry questions which are about Raoult's law
need all correct answers plz
'Solution B' was prepared by mixing 2.41 g of liquid propanone with 3.10 g of liquid butanone at 30°C in a closed container.
The vapour pressure of pure propanone (C3H6O, molar mass = 58.1 g/mol) at 30°C is 285 mm Hg and that of pure butanone (C4H8O, molar mass = 72.1 g/mol) is 121 mm Hg at the same temperature. From this information, and assuming Raoult's Law applies to his mixture, calculate the values below at 30°C.
(a) the mole fraction of propanone in Solution B
Answer:
(b) the mole fraction of butanone in the solution
Answer:
(c) the partial pressure (in mm Hg) of propanone above Solution B.
Answer:
(d) the partial pressure (in mm Hg) of butanone above Solution B.
Answer:
(e) the mole fraction of propanone in the vapour phase.
Answer:
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