1
answer
0
watching
232
views
17 Nov 2019
Calculate the ratio of [PbT]/[HT^2] for NTA in equilibrium with PbCO_3 in a medium having [HCO_3] = 3 times 10^-3 M by considering the following reaction: PbCO_3(s), + HT^2- PbT + HCO_3^- Use the following constants for your calculation. Solubility of PbCO_3(s): K_sP = [Pb^2+][CO_3^2-] = 1.48 times 10^-13 Formation constant for PbT: K_f = [PbT]/([Pb^2+][T^3]) = 2.45 times 10^11 Equilibrium constant for HT^2-/T^3-: K_a3 = ([H^+)[T^3-])/[HT^2-] = 5.25 times 10^-11 Equilibrium constant for HCO_3^-/CO_3^2-: K_a2 = ([H^+][CO_3^2-])/[HCO_3^-] = 4.69 times 10^-11 If [HCO_3] concentration increases, would the solubility of PbCO_3(s) increases or decreases?
Calculate the ratio of [PbT]/[HT^2] for NTA in equilibrium with PbCO_3 in a medium having [HCO_3] = 3 times 10^-3 M by considering the following reaction: PbCO_3(s), + HT^2- PbT + HCO_3^- Use the following constants for your calculation. Solubility of PbCO_3(s): K_sP = [Pb^2+][CO_3^2-] = 1.48 times 10^-13 Formation constant for PbT: K_f = [PbT]/([Pb^2+][T^3]) = 2.45 times 10^11 Equilibrium constant for HT^2-/T^3-: K_a3 = ([H^+)[T^3-])/[HT^2-] = 5.25 times 10^-11 Equilibrium constant for HCO_3^-/CO_3^2-: K_a2 = ([H^+][CO_3^2-])/[HCO_3^-] = 4.69 times 10^-11 If [HCO_3] concentration increases, would the solubility of PbCO_3(s) increases or decreases?
Hubert KochLv2
30 Jun 2019