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A pure sample of R enantiomer of a compound has a specific rotation, (alpha) of +20 degrees. A solution containing .2g/mL of a mixture of enantiomers rotates plane polarized light by -2 degrees in a 1 dm polarimeter. What is the enantiomeric excess of the mixture?

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Beverley Smith
Beverley SmithLv2
10 May 2019

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Related questions

The specific rotation of Compound X is +15.2. A mixture of Compound X and its

enantiomer are placed in the polarimeter and the observed rotation is -5.1.

Which enantiomer is in excess?

Calculate the enantiomeric excess.

Calculate the percentage of each enantiomer in the mixture.

PART A. A 1:4 mixture of the (R) and (S)-enantiomers of compound A has a specific rotation of +40o.

I) Calculate the enantiomeric excess for this mixture.

II) What is the specific rotation for the pure (R)-enantiomer?

III) Calculate the specific rotation for a 9:1 mixture of the (R)- and (S)-enantiomers of A.

PART B. The pure (S)-enantiomer of compound B has a specific rotation of +60o.

I) Calculate the specific rotation for a 2:1 mixture of (R) and (S)-enantiomers of B.

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What is the enantiomeric excess of a mixture whose(+) enantiomer has a specific rotation of 10 degrees and the mixture of (+) and (-)has a specific rotation of 5 degrees?

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