Provide the mechanism for the haloform reaction in part B of this experiment
Also explain how the added acetone in step 4 destroys any unreacted hypochloride.
Haloform Reaction Add about 1.0 g (measured accurately) of acetophenone to 40 mL of bleach solution (5% NaOCl in water - this reactant should be included in your table of reagents!) in a 100 mL round bottom flask equipped with a magnetic stirrer. Clamp the flask in the fume hood above a stir plate. After the initial reaction has subsided, boil the reaction mixture gently for 5-10 minutes using a heating mantle. After 15 minutes, take a TLC of your reaction mixture. Add 0.5 mL of acetone to destroy any unreacted hypochloride (how?) and boil gently for another 15 minutes to remove the chloroform and unreacted acetone. If your solution is very dark, add a small amount of decolorizing charcoal and filter the solution while it is still hot. Pour the mixture into a 125 mL Erlenmeyer flask using a filter funnel and place the flask in an ice bath. Acidify the solution by adding concentrated HC1 drop-wise until the pH is near 1 and no more precipitate forms. Keep the mixture in the ice bath for an additional 5 minutes to complete the precipitation. Filter the product by suction filtration using a Buchner funnel. Wash the crystals with about 5 - 10 mL of cold water and let them dry. Determine the melting point and the yield of your product once the crystals have dried at the end of the lab period.
