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17 Nov 2019
Consider the following cell reaction: Pb^2 + Zn rightarrow Pb + zn^2+ E degree = 0.637 V In this case, the reaction will proceed spontaneously. True False The correct cell notation for the following reaction Ni(s) + Cd^2+(aq) rightarrow Cd(s) + Ni^2 (aq) is Ni(s);NI^2+ (aq)||Cd^2+ (aq)|Cd(s). because: Nickel is oxidized, the cadmium ion is reduced and the oxidation step is always written on the left side of the cell notation. Cadmium is oxidized, the nickel ion is reduced end the oxidation step it always written on the left side of the cell notation. Nickel is reduced, the cadmium ion is oxide and the oxidation step is always written on the right side of the cell notation. Nickel is oxidized, the cadmium ion is reduced and the oxidation step is always written on the right side of the cell notation.
Consider the following cell reaction: Pb^2 + Zn rightarrow Pb + zn^2+ E degree = 0.637 V In this case, the reaction will proceed spontaneously. True False The correct cell notation for the following reaction Ni(s) + Cd^2+(aq) rightarrow Cd(s) + Ni^2 (aq) is Ni(s);NI^2+ (aq)||Cd^2+ (aq)|Cd(s). because: Nickel is oxidized, the cadmium ion is reduced and the oxidation step is always written on the left side of the cell notation. Cadmium is oxidized, the nickel ion is reduced end the oxidation step it always written on the left side of the cell notation. Nickel is reduced, the cadmium ion is oxide and the oxidation step is always written on the right side of the cell notation. Nickel is oxidized, the cadmium ion is reduced and the oxidation step is always written on the right side of the cell notation.
Jamar FerryLv2
5 Feb 2019