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18 Nov 2019


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Trinidad Tremblay
Trinidad TremblayLv2
14 May 2019

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Related questions

Suppose it took 11.5 mL of 0.112 M NAOH solution to neutralize the acid solution and that you used 0.592 g of green crystals to prepare the original 50.0 mL solution (of which only 10.00 mL is analyzed for Co at a time). Calculate the mass of cobalt in the sample, the percent cobalt and the percent error.

I did the following two calculations:

Calculation of concentration (M) of 1 mL of cobalt (II) in diluted solution with 9 mL of deionized water

C1*V1 = C2*V2 (I)
0.1 M cobalt * 0.001 L cobalt = C2 * 0.01 L
C2 = (0.1 M * 0.001 L)/0.01 L = 0.01 M

Calculation of concentration (M) of unknown sample
Y = mx + b = 3.43x - 0.0094 (II)
X = (y-b)/m = (0.22+0.0094)/3.43 = 0.067 M

And I cannot figure out the final calculation:

Calculation of mg of cobalt in 1 kg of soil
M = moles/volume

I've attached a picture that could provide further context.

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