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18 Nov 2019
Answer and solution please
Another buffer found in blood is based on the equilibrium between dihydrogen phosphate and monohydrogen phosphate. The reaction is shown below: H_2PO_4^-(aq) + H_2O_(I) rightarrow H_3O^+_(aq) + HPO_4^-2_(aq) If the pH of a blood sample was 7.10, what would you calculate as the ratio of [H_2PO_4^-) to [HPO_4^-2]? (K_a1 = 7.5 times 10^-3, K_a2 = 6.2 times 10^-8, K_a3 = 3.6 times 10^-13)
Answer and solution please
Another buffer found in blood is based on the equilibrium between dihydrogen phosphate and monohydrogen phosphate. The reaction is shown below: H_2PO_4^-(aq) + H_2O_(I) rightarrow H_3O^+_(aq) + HPO_4^-2_(aq) If the pH of a blood sample was 7.10, what would you calculate as the ratio of [H_2PO_4^-) to [HPO_4^-2]? (K_a1 = 7.5 times 10^-3, K_a2 = 6.2 times 10^-8, K_a3 = 3.6 times 10^-13)
Jamar FerryLv2
30 Jul 2019