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18 Nov 2019
If K_c = 0.0055 for the reaction N_2(g) + 3 H_2(g) 2 NH_3(g) runs at 390.0 K, what is K_c at 390.0 K for the reaction: 1/3 N_2(g) + H_2(g) 2/3 NH_3(g) Can you see the algebraic relationship between these two equilibrium expressions? K_c = [NH_3]^2/[H_2]^3 [N_2] K'_c = [NH_3]^2/3/[H_2][N_2]^1/3
If K_c = 0.0055 for the reaction N_2(g) + 3 H_2(g) 2 NH_3(g) runs at 390.0 K, what is K_c at 390.0 K for the reaction: 1/3 N_2(g) + H_2(g) 2/3 NH_3(g) Can you see the algebraic relationship between these two equilibrium expressions? K_c = [NH_3]^2/[H_2]^3 [N_2] K'_c = [NH_3]^2/3/[H_2][N_2]^1/3
Trinidad TremblayLv2
7 Feb 2019