Hey there, could you please help me with Part C of this question? I can't get it unfortunately... The E of the cell is 0.57 V which I calculated in Part A. Thanks in advance!
A voltaic cell consists of a Zn/Zn half-cell and a Ni/Ni2+ half-cell at 25 C. The initial concentrations of Ni2+ and Zn are 1.80 mol L 1 and 0.100 mol L respectively. Zn2 (ag) +2e Zn(s) Eo 0.76 V Ni (ag) 2 e Ni(s) Eo 0.23 V Ecell 0.57 V Submit My Answers Give Up Correct Part B What is the cell potential when the concentration of Ni has fallen to 0.600 mol L 1? Express your answer to two decimal places and include the appropriate units. 0.52 V Submit My Answers Give Up Correct Part C What are the concentrations of Ni and Zn when the cell potential falls to 0.46 V? Express your answers using two significant figures separated by a comma 2-t 2-+ mol L Zn' Submit My Answers Give Up