At 298 K, 1.30 mol BrCl(g) is introduced into a 12.0 âL vessel, and equilibrium is established in the reaction.
BrCl(g)â0.5Br2(g)+0.5Cl2(g):

1.Calculate the amount of BrCl(g) present when equilibrium is established. [Hint: Use ÎG0[Br2(g)]=3.11kJ/mol, ÎG0[BrCl(g)]=â0.98kJ/mol.]

2.Calculate the amount of Br2(g) present when equilibrium is established.

3.Calculate the amount of Cl2(g) present when equilibrium is established.

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28 Apr 2019

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For the equilibrium Br2(g) + Cl2(g) â 2 BrCl(g) the equilibrium constant Kp is 7.0 at 400 K. If a cylinder is charged with BrCl(g) at an initial pressure of 1.00 atm and the system is allowed to come to equilibrium what is the final (equilibrium) pressure of BrCl?

For the equilibrium the equilibrium constant is 7.0 at 400 . If a cylinder is charged with at an initial pressure of 1.00 and the system is allowed to come to equilibrium what is the final (equilibrium) pressure of ?

	0.31 atm
	0.15 atm
	0.45 atm
	0.57 atm
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The reaction of an organic acid with an alcohol, in organic solvent, to produce an ester and water is commonly done in the pharmaceutical industry. This reaction is catalyzed by strong acid (usually H2SO4). A simple example is the reaction of acetic acid with ethyl alcohol to produce ethyl acetate and water:
CH3COOH(solv)+CH3CH2OH(solv)âCH3COOCH2CH3(solv)+H2O(solv)
where "(solv)" indicates that all reactants and products are in solution but not an aqueous solution. The equilibrium constant for this reaction at 55 âC is 6.68. A pharmaceutical chemist makes up 15.0 L of a solution that is initially 0.275M in acetic acid and 3.85M in ethanol.

At equilibrium, how many grams of ethyl acetate are formed?

A mixture of 0.02471 mol of Cl2, 0.02489 mol of H2O, 0.06124 mol of HCl, and 0.03210 mol of O2 is placed in a 1.0-L steel pressure vessel at 1977 K. The following equilibrium is established:2 Cl2(g) + 2 H2O(g) 4 HCl(g) + 1 O2(g)At equilibrium 0.01509 mol of Cl2 is found in the reaction mixture.(a) Calculate the equilibrium partial pressures of Cl2, H2O, HCl, and O2.Peq(Cl2) = .Peq(H2O) = .Peq(HCl) = .Peq(O2) = .(b) Calculate KP for this reaction.KP = .

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