Calculating [H30+] and [OH-] In Solutions Water is amphoteric and ionizes according tothe chemical equation H20 H20 H30 OH In pure water, the concentrations ofHo and oH are both equal to 1x10 7 M and the ion nt of water (KE) is 1 x 10 14 M. 1 x 10-7 M 1 x 10 M 1 x 10 The equation for the ion product constant of water reveals that a concentrations of hydronium ion (Hao l) and hydroxide on (oH are inversely proportional since they are on the same side of the equation, If a solution's concentration of HJo increases, then its concentration of OH decreases. If a solution's concentrafion of Hso decreases, then its concentration of OH increases. This equation also reveals that if the concentration of either the hydronium ion or the hydroxide ion is known, then the concentration of the other can be calculated using the ion product constant of water. Part A Determine whether the following hydroxide (loH bcorrespond toacidio, basic, or neutral solutions by estimating their corresponding hydronium ion product constant of water Hydronium ion concentration H30 Solution condition Greater than 1 x 10 7 M Equal to 1 x 10 M Neutral Less than 1 x 10-7 M It may help to keep the following equation in mind as you work 1 x 10 MM 1 x 10 T M 1 x 10
The reaction was run three times with different initial concentrations of the reactants yielding the following rates:
b)Determine the reaction order with respect to HBPB2-
c)Determine the reaction order with respect to OH-
d)Calculate the rate constant for this reaction at 20 oC
e)What is the ârate lawâ for this reaction?
f)What other information do you need to calculate the activation energy for this reaction?
2. Why is it better to transfer one group of solutions into one flask and a second group into a second flask and then mix them, instead of pipetting the solutions sequentially into the same flask?
3. What will be the concentration of [I-] in the reaction flask after mixing (See Run #6): 1.0 ml starch + 2.0 mL 1.2 x10-2 M Na2S2O3 + 4.0 mL 0.20 M KI + 4.0 mL 0.20 M KNO3 + 4.0 mL 0.20 M (NH4)2S2O8 + 4.0 mL 0.20 M (NH4)2SO4 ?
4. What will be the concentration of [S2O82-] in the same reaction mixture as above?