Can anybody help me with this. Thanks in advance. I donât know how to solve 1/1^2-1/infinite square

2a For hydrogen, ionization would correspond to moving the electron from n=l tãÎ¦. Using equation (4), calculate the ionization energy of one atom of hydrogen in joules. b. Calculate the ionization energy of atomic hydrogen in kJ/mol.

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Lelia LubowitzLv2

5 Oct 2019

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3. The energy needed for the following process is 1.96 x 10⁴ kJ/mol:

Li(g) â Li³⁺(g) + 3e^- ; I₁ + I₂ + I₃ = 1^st, 2^nd, 3^rd ionization energies. The first

ionization energy of lithium is 520 kJ/mol, Li(g) â Li⁺(g) + e^-, I₁ , 1^st ionization energy.

Calculate the second ionization energy of lithium, Li⁺(g) â Li²⁺(g) + e^- , I₂ , 2^nd ionization

energy.

Energy needed to remove three electrons = I₁ + I₂ + I₃

Z = 3; n= 1

I₃ = ÎE = E_â - E₃

I₃ = -(2.18 x 10^-18 J)(3)² () + (2.18 x 10^-18 J)(3)² () ; See equation in #8.93, p 284

I₃ = +1.96 x 10^-17 J

I₃ = +1.96 x 10^-17 J (6.022 x 10²³ ions/1 mol) = 1.18 x 10⁷ J/mol â 1.18 x 10⁴ kJ/mol

Energy needed to remove three electrons = I₁ + I₂ + I₃

1.96 x 10⁴ kJ/mol = 520 kJ/mol + I₂ + 1.18 x 10⁴ kJ/mol

I₂ = 7.28 x 10³ kJ/mol (7300 kJ/mol; Table 8.2)

3 of 3

Using this information and the procedure used to solve problem #8.93, p 284, determine the effective nuclear charges, Z_eff, during the 1^st, 2^nd, and 3^rd ionizations of lithium (i.e. when the first electron is removed, when the second is removed and when the third is removed).

How do you answer 11 and 12?