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19 Nov 2019
The rate constant for the formation of NO_2 from the oxidation of NO by O_3 is 5 Times 10^-14 molecule^-1 cm^3 sec^-1, whereas for the competing reaction with O_2 it is 2 Times 10^-37 molecule^-2 cm^6 sec^-1. 2NO + O_2 rightarrow 2NO_2 NO + O_3 rightarrow NO_2 + O_2 If the concentration of NO is 55 ppb and ozone concentration is 28 ppb, calculate the rates for these two reactions and determine which one is the dominant process. Conc. of O_2 = 20.95% Molar volume at 25 degree C = 24.47 dm^3 N_A = 6.022 Times 10^23 mol^-1
The rate constant for the formation of NO_2 from the oxidation of NO by O_3 is 5 Times 10^-14 molecule^-1 cm^3 sec^-1, whereas for the competing reaction with O_2 it is 2 Times 10^-37 molecule^-2 cm^6 sec^-1. 2NO + O_2 rightarrow 2NO_2 NO + O_3 rightarrow NO_2 + O_2 If the concentration of NO is 55 ppb and ozone concentration is 28 ppb, calculate the rates for these two reactions and determine which one is the dominant process. Conc. of O_2 = 20.95% Molar volume at 25 degree C = 24.47 dm^3 N_A = 6.022 Times 10^23 mol^-1
Collen VonLv2
5 Mar 2019