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19 Nov 2019
The reaction 2NO_2 rightarrow 2NO + O_2 obeys the rate law: delta[O_2]/delta t = (1.40 times 10^-2 sec) [NO_2]^2 at 500. K. If the initial concentration of NO_2 is 1.00 M, how long will it take for the [NO_2] to decrease to 14.2% of its initial value? A) 61.3 s B) 139 s C) 432 s D) 1.40 times 10^-2 s E) cannot be determined from this data
The reaction 2NO_2 rightarrow 2NO + O_2 obeys the rate law: delta[O_2]/delta t = (1.40 times 10^-2 sec) [NO_2]^2 at 500. K. If the initial concentration of NO_2 is 1.00 M, how long will it take for the [NO_2] to decrease to 14.2% of its initial value? A) 61.3 s B) 139 s C) 432 s D) 1.40 times 10^-2 s E) cannot be determined from this data
Casey DurganLv2
5 Aug 2019