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19 Nov 2019
Can anyone explain this question. The answer to A is elimination, but since it's a secondary alkyl halide and a strong base, SN2 and E2 can occur, so how do you know if it is elimination. Also the answer to part b is E2 but I don't understand why.
3. Deuterium (D) is the isotope of hydrogen with mass number 2, with a proton and a neutron in its nucleus. The chemistry of deuterium is nearly identical to the chemistry of hydrogen, except that the C-D bond is slightly stronger than the C-H bond. Reaction rates tend to be slower if a C-D bond (as opposed to C-H bond) is broken in a rate determining step This effect on rate is called a kinetic isotope effect. a. Predict whether the following two products are formed by SN1ISN2 or EllE2: KOH CH CHCH CH3CH2OH CH CH CH3 CH CHCH Elimination product Substitution product b. When the deuterated form of the alkyl halide reacts under the same conditions, the rate of formation of the substitution product is unchanged, while the rate of formation of the elimination product is slowed by a factor of seven. Br KOH CD3 CHCD3 CH-CD CD. CD CH CD CH3CH2OH 7 times slower rate unchanged must be 8 2 e in E 2 we are steins lore bead the ROS How does this result allow you to see if your predictions are correct?
Can anyone explain this question. The answer to A is elimination, but since it's a secondary alkyl halide and a strong base, SN2 and E2 can occur, so how do you know if it is elimination. Also the answer to part b is E2 but I don't understand why.
3. Deuterium (D) is the isotope of hydrogen with mass number 2, with a proton and a neutron in its nucleus. The chemistry of deuterium is nearly identical to the chemistry of hydrogen, except that the C-D bond is slightly stronger than the C-H bond. Reaction rates tend to be slower if a C-D bond (as opposed to C-H bond) is broken in a rate determining step This effect on rate is called a kinetic isotope effect. a. Predict whether the following two products are formed by SN1ISN2 or EllE2: KOH CH CHCH CH3CH2OH CH CH CH3 CH CHCH Elimination product Substitution product b. When the deuterated form of the alkyl halide reacts under the same conditions, the rate of formation of the substitution product is unchanged, while the rate of formation of the elimination product is slowed by a factor of seven. Br KOH CD3 CHCD3 CH-CD CD. CD CH CD CH3CH2OH 7 times slower rate unchanged must be 8 2 e in E 2 we are steins lore bead the ROS How does this result allow you to see if your predictions are correct?
Nestor RutherfordLv2
11 Jun 2019