1) draw the bonding & anti bonding molecular orbital for the pair of C-H bonds in Fig. 3.
2) explain why staggered conformation is more stable than the eclipsed conformation.
Hyperconjugation in conformational Analysis questions follow.) Now that you can draw both the bonding and antibonding Mos for a C-H bond, let's consider the molecule of ethane below. In cla we said that when two adjacent C-H bonds are planar solid lines in Figure 3), the bonding one C-H bond was able to some of its electron density to the the other and vice versa. This density donation from a filled orbital to an adjacent empty orbital is called hyperconjugation. This effect can be stabilizing since it delocalizes MO must be the lectron density over more atoms. Importantly, in order for hyperconjugation to occur, the filled and adjacent empty ble to overlap. Remember that as you consider the questions below. draw draw antibonding bonding draw antibonding Figure 3: Staggered and eclipsed conformations of ethane. Draw the bonding and antibonding Mo orbital for the pair of adjacent C-H bonds indicated in Figure 3.Draw them directly on top of the Lewis structures in Figure 3. Let the letter represent the nucleus of each atom. Use your answer to question 7 for guidance Using the Mos you've superimposed on the Lewis structures in Figure 3, explain why the staggered conformation is more stable than the eclipsed conformation. (Do not use the steric argument.)
