1
answer
0
watching
118
views
23 Nov 2019

(a) 0.0053 M KOH

[OH-] = pH =



(b) 0.0301 g of LiOH in 450.0 mL of solution

[OH -] = pH =



(c) 59.4 mL of 0.00550 M Sr(OH)2 diluted to 500 mL

[OH -] = pH =



(d) A solution formed by mixing 54.0 mL of 0.000890 M Sr(OH)2 with65.0 mL of 2.1 x 10-3 M KOH

[OH -] = pH =


For unlimited access to Homework Help, a Homework+ subscription is required.

Casey Durgan
Casey DurganLv2
20 Jun 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Start filling in the gaps now
Log in