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For the following formula, C10H14, calculate the IHD...
Then, the type of unsaturation that might be present is....
a. no unsaturation; no multiple bonds or ring closings
b. one double bond or one ring closing
c. three double bonds or three rings closing; or two double bondsand one ring closing; or one double bond and two rings closing; orone triple bond and one double bond;or one triple bond and one ringclosing
d. many possibilities, most likely benzene ring
For the following formula, C10H14, calculate the IHD...
Then, the type of unsaturation that might be present is....
a. no unsaturation; no multiple bonds or ring closings
b. one double bond or one ring closing
c. three double bonds or three rings closing; or two double bondsand one ring closing; or one double bond and two rings closing; orone triple bond and one double bond;or one triple bond and one ringclosing
d. many possibilities, most likely benzene ring
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Jarrod RobelLv2
18 Jul 2019
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