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23 Nov 2019

How do I find the collision rate (s/m^3) for a known molecule giventhe collisional cross section (nm^2) of the known molecule; knownpressure, temperature, diameter and length of the cylinder that themolecules are inside?

My thinking:
[I assume that collision Rate (Z) =SQRT(2)(speed_avg)(PI)(d^2)(N/V) ; Also, I know thatsigma=PId^2
I do not know what to use for d^2; N/V I am assume is mol/L whichcan be calculated by P/(K_B*T) ; gives mols of molecules insidecylinder per volume; where K_B is 1.3806503*10^-23 m^2 * kg/(s^2K).

I know that the collisional cross section of two molecules is r =0.5(r_a + r_b) and therefore, I might be able to use, for onemolecule with known collisional cross section radius, Z =PI(r^2)(4RT/(PI*mu)) where mu for a molecule, such as CO_2, is themolecular weight.]

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