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26 Nov 2019

The transition from v=0, J=1 to V=1, J=2 is one of the fundamentalvibrations of NO (a radical) found at 1900 cm^-1 while thetransition v=0, J=3 to v=1, J=2 is found at 1870 cm^-1

This vibration will show which of the following branches?

(a)P (b)Q (c)R (d)P,Q (e)P,R (f)Q,R (g)P,Q,R

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Anyone plz answer these questions? Especially c) read the questions carefully and answer fully not only wavenumbers but also F and rotational constant

Match the statement to the correct answer. (Some reagents can be used more than once.) The flowchart along with the report sheets in experiment 5 should be very helpful.

A	6M Nitric Acid (HNO₃)
B	Colbalt Nitrate (Co(NO₃)₂)
C	Disodium EDTA (Na₂EDTA)
D	Aluminum Nitrate (Al(NO₃)₃)
E	Zinc Nitrate (Zn(NO₃)₂
F	Barium Nitrate (Ba(NO₃)₂)
G	6M Hydrochloric Acid (HCl)
H	OH^-, CO₃^2-, and PO₄^3-
I	Lead chloride (PbCl₂(s))
J	0.1M sodium carbonate (Na₂CO₃)
K	NH₄⁺(aq) and OH^-(aq)
L	Silver chloride (AgCl(s))
M	Anion
N	Lead Nitrate (0.1M Pb(NO₃)₃)
O	Silver Nitrate (AgNO₃)
P	Cation
Q	1M ammonium hydroxide (NH₄OH)
R	Na⁺, NO₃^-, and NH₄⁺
S	None of the above

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The transition from v=0, J=1 to V=1, J=2 is one of the fundamentalvibrations of NO (a radical) found at 1900 cm^-1 while thetransition v=0, J=3 to v=1, J=2 is found at 1870 cm^-1

This vibration will show which of the following branches?

(a)P (b)Q (c)R (d)P,Q (e)P,R (f)Q,R (g)P,Q,R

Related textbook solutions

Basic Chemistry

Principles of Chemistry Molecular Approach

Chemistry: Structure and Properties

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Chemistry: A Molecular Approach

Principles of Chemistry: A Molecular Approach

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The transition from v=0, J=1 to V=1, J=2 is one of the fundamentalvibrations of NO (a radical) found at 1900 cm^-1 while thetransition v=0, J=3 to v=1, J=2 is found at 1870 cm^-1This vibration will show which of the following branches?(a)P (b)Q (c)R (d)P,Q (e)P,R (f)Q,R (g)P,Q,R

Related textbook solutions

Basic Chemistry

Principles of Chemistry Molecular Approach

Chemistry: Structure and Properties

Principles of Chemistry Molecular Approach

Chemistry: A Molecular Approach

Chemistry: A Molecular Approach

Principles of Chemistry: A Molecular Approach

Chemistry: The Central Science

Related questions

Weekly leaderboard

The transition from v=0, J=1 to V=1, J=2 is one of the fundamentalvibrations of NO (a radical) found at 1900 cm^-1 while thetransition v=0, J=3 to v=1, J=2 is found at 1870 cm^-1

This vibration will show which of the following branches?

(a)P (b)Q (c)R (d)P,Q (e)P,R (f)Q,R (g)P,Q,R