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26 Nov 2019
A volume of 40.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the solution if 19.2 mL of 1.50 M H2SO4 was needed? The equation is 2KOH(aq)+H2SO4(aq)=K2SO4(aq0+2H2O(l)
A volume of 40.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the solution if 19.2 mL of 1.50 M H2SO4 was needed? The equation is 2KOH(aq)+H2SO4(aq)=K2SO4(aq0+2H2O(l)
Bunny GreenfelderLv2
10 Nov 2019
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