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27 Nov 2019

In an experiment, a solution containing 0.0837 M analyte (X) and 0.0666 M standard (S) gave peak areas of Ax=423 and As=347. To determine an unknown concentration of the analyte, 10.0 mL of 0.0146 M standard was added to 10.0 mL of the unknown solution then the mixture was diluted to 25.0 mL in a volumetric flask. Analysis of this mixture resulted in peak areas of Ax=553 and As=582. What is the concentration of the analyte in the unknown solution?

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Trinidad Tremblay
Trinidad TremblayLv2
12 Jun 2019

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Related questions

Consider a solution containing 3.78 mM of an analyte, X, and 1.39 mM of a standard, S. Upon chromatographic separation of the solution peak areas for X and S are 4001 and 10867, respectively. Determine the response factor for X relative to S.

a) F = ?

To determine the concentration of X in an unknown solution, 1.00 mL of 8.50 mM S was added to 3.00 mL of the unknown X solution and the mixture was diluted to 10.0 mL. After chromatographic separation, this solution gave peak areas of 6299 and 4703 for X and S, respectively.

b) Determine the concentration of S (in mM) in the 10.0 mL solution.

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d) Determine the concentration of X (in mM) in the unknown solution.

A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3,473 and 10,222 respectively in a chromatographic analysis. tThe, 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X and the mixture was diluted to 10.0 mL. This solution gave peak areas of 5,428 and 4,431 for X and S, respectively. Calculate the concentration of X in the ORIGINAL unknown. (please work out problem!!!)

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