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Part AWhat volume of the 11.6 M HCl must the assistant add to a one liter volumetric flask so that the concentration of the stock solution will be 0.64 M after dilution to the mark with water?Part BWhat is the pH of the stock solution? (Remember the significant figure rules for logarithms!)You will now use this 0.56 M HCl solution to carry out a series of dilutions, measuring the pH of each diluted sample.Sample A will be produced by pipetting 1.00 mL of the stock solution into a 25 mL volumetric, and diluting to volume with distilled water.Sample B will be produced by pipetting 1.00 mL of sample A into a 25 mL volumetric, and diluting to volume with distilled water.Sample C will be produced by pipetting 1.00 mL of sample B into a 25 mL volumetric, and diluting to volume with distilled water.Sample D will be produced by pipetting 1.00 mL of sample C into a 25 mL volumetric, and diluting to volume with distilled water.Sample E will be produced by pipetting 1.00 mL of sample D into a 25 mL volumetric, and diluting to volume with distilled water.Sample F will be produced by pipetting 1.00 mL of sample E into a 25 mL volumetric, and diluting to volume with distilled water.Part CCalculate theCl- concentration in sample A.Part DCalculate H+ and the pH for sample A.Part ECalculate the Cl- concentration in sample B.Part FCalculate H+ and the pH for sample B.part gCalculate Cl- the concentration in sample C.Part HCalculate H+ and the pH for sample C.Part ICalculate Cl- the concentration in sample D.Part JCalculate H+ and the pH for sample D.Part KCalculate the Cl-concentration in sample E.Part LCalculate H+ and the pH for sample E.Part MCalculate the Cl-concentration in sample F.Part NCalculate H+ and the pH for sample F.

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Keith Leannon
Keith LeannonLv2
13 May 2019

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