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27 Nov 2019

a titration of of 200ml of 1.00 M HA was done with 1.00 M Naoh. For the monoprotic acid HA Ka=2.5x10^-5.Calculate the pH after 100 mL of 1.00 M NaOH has been added

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Bunny Greenfelder
Bunny GreenfelderLv2
15 Aug 2019

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Related questions

A titration of 200.0 mL of 1.00 M H2A was done with 1.38 M NaOH. For the diprotic acid H2A, Ka1 = 2.5 ´ 10–5, Ka2 = 3.1 ´ 10–9. Calculate the pH after 100.0 mL of 1.38 M NaOH have been added.

(The answer is E, I couldn't get it. Could anyone explain it by steps? I have the PH at about 13)

A)

9.05

B)

8.86

C)

5.14

D)

9.90

E)

4.95

A titration of of was done with . For the diprotic acid , . Calculate the pH after of have been added.

A.  

B.  

C.  

D.  

E.  

A titration of 200.0 mL of 1.00 M H2A was done with 1.17 M NaOH.for the diprotic acid H2A, Ka1=2.5*10^-5, Ka1=3.1*10^-9. Calculatethe pH after 600.0 mL of 1.17 M NaOH have been added.
A) 13.577
B) 0.423
C) 13.798
D) 0.202
E) 9.577

I know the answer is A) 13.577, but I have NO clue how to getthere. This is what I have so far:

1.17 M NaOH * 0.6 L = 0.702 mol NaOH

H2A --> H+ + HA-
before reaction 0.2 mol 0 mol 0mol


HA- --> H+ + A-

I have no idea where to go from here. Any help would be muchappreciated!

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