Part A: There is unknown solution whose information is:
-Mass: 0.7638 grams
-Initial Buret reading: 0.00 mL
-Final buret reading: 26.05 mL
-Vol of the KMnO4: 43.75 mL
- The unknown was mixed with 100mL deionized Water and 25 Ml of 3 MH2SO4(that contains some manganese (II) sulfate). then the mixedsolution was put on a hot plate and then some prepared permanganatesolution and titrated the oxalate wit it.
1. Calculated mass of Na2C2O4 in the unknown?
2. Percentage of Na2C2O4 in the unknown?
Part B.
In this lab the oxidizing agent is potassium Permanganate ion. thereducing agent is sodium oxalate. So during the titration if thesolution turns to a muddy brown int indicates the formation ofMNO2. Explain how the formation of the MnO2 affects the results ofthe the titration.
Part A: There is unknown solution whose information is:
-Mass: 0.7638 grams
-Initial Buret reading: 0.00 mL
-Final buret reading: 26.05 mL
-Vol of the KMnO4: 43.75 mL
- The unknown was mixed with 100mL deionized Water and 25 Ml of 3 MH2SO4(that contains some manganese (II) sulfate). then the mixedsolution was put on a hot plate and then some prepared permanganatesolution and titrated the oxalate wit it.
1. Calculated mass of Na2C2O4 in the unknown?
2. Percentage of Na2C2O4 in the unknown?
Part B.
In this lab the oxidizing agent is potassium Permanganate ion. thereducing agent is sodium oxalate. So during the titration if thesolution turns to a muddy brown int indicates the formation ofMNO2. Explain how the formation of the MnO2 affects the results ofthe the titration.
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