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A 0.15 M solution of a weak acid is found to be 1.3 ionized. What is the Ka of the acid?

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Greg Montoya
Greg MontoyaLv10
16 Nov 2020

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Related questions

A 0.15 M solution of a weak acid is found to be 1.3% ionized. Whatis its Ka?
Explanation please!

1. 25.00 mL of a solution of 0.100 M uric acid(Ka = 1.3 x10-4), what is thepH?


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25.00 mL of a solution of 0.100 M uric acid(Ka = 1.3 x10-4), andthen adds 5.00 mL of 0.15 M HCl, what is the pH?


25.00 mL of a solution of 0.100 M uric acid(Ka = 1.3 x10-4), andthen adds 15.00 mL of 0.15 M NaOH, what is the pH?


25.00 mL of a solution of 0.100 M uric acid(Ka = 1.3 x10-4), andthen adds 16.666667 mL of 0.15 M NaOH, what is the pH?


25.00 mL of a solution of 0.100 M uric acid(Ka = 1.3 x10-4), andthen adds 5.00 mL of 0.15 M NaOH, what is the pH?


Please show step by step explanation.thanks.

A weak acid with Ka = 2.2 x 1-^-4 is 1.5% ionized in a 1.0 M solution. WHat would be the percent ionization in a 0.010 M solution of the same weak acid.

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