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If the Ksp of Ba(IO3)2 at 25°C is 6.0 X 10-10, what is the molar solubility of Ba(IO3)2?

In definition, solubility or molar solubility of a compound is the concentration of the dissolved solids in a saturated solution. Molar solubility can be solved using the given solubility product constant. 

For the compound C2D3, we can express this as the concentration of C and D in the aqueous solution. 

To solve for the molar solubility: 

Let S = molar solubility of C2Din mol L-1

[C] = 2S

[D] = 3S

 

Substituting this to the solubility product constant, Ksp formula, we'll have:

  

  

  

  

 

Thus, the molar solubility is 3.958 x 10 -5 M. 

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Cyrielle Lorio
Cyrielle LorioLv10
27 Oct 2020

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