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orangebuffalo627Lv1

11 Dec 2019

Consider the combustion of methane: Ch_4(g)+2O_2(g) → CO_2(g)+2H₂O_(g)

Suppose 2.8 moles of methane is allowed to react with 3 moles of oxygen, what is the limiting reactant?

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Related questions

Calculate the work (in kJ) when 1.10 moles of methane react with excess oxygen at 391 K:

CH4(g) + 2O2(g) â CO2(g) + 2H2O(l)

Calculate the work (in kJ) when 1.20 moles of methane react with excess oxygen at 318 K:

CH₄(g) + 2O₂(g) â CO₂(g) + 2H₂O(l)

Methane,CH4, reacts with oxygen to form CO2 and h2o:
CH4(g)+2O2(g) --> CO2(g) + 2H2O(g)
Calculate the total number of moles of co2 and h2o that form when10.0g of methane reacts with 20.0g of oxygen

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