Question

If 0.20 moles of C6H12O6 are mixed with 1.00 moles of O2 in thereaction below, how much of each reactant is left?

C₆H₁₂O₆ + 6O₂ -->6CO₂ + 6H₂O

a.) 0 moles C6H12O6 and 0.2 moles O2

b.) 0 moles C6H12O6 and 0 moles O2

c.) 0.033 moles of C6H12O6 and 0 moles of O2

d.) 0 moles C6H12O6 and 0.033 moles O2